thread: What Do You Look Like? (V8)
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  #290  
09-07-2007, 03:08 PM
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Wil
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:
well it would be totally correct if it was
cos(x)^2 + sin(y)^2 with x = y
I feel compelled to point out that that should be cos2 x rather than cos x2, and likewise for the sine function.
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Last edited by Wil; 09-07-2007 at 03:13 PM..